Bienvenido

Bienvenido a este blog. (Remembering that our lectures should be in English) I hope this blog will serve us as a platform to continue our course via the internet. As a first step, let me upload the corrected version of the homework assignment 5.

Comentarios

Publicar un comentario

Entradas más populares de este blog

Work for an ideal gas in a 3D container (corrected)

Imagen
Using the differential al work calculated on exercise 6.2: 1. How can we use the result to obtain DW for an ideal gas in a 3D container? What is the interpretation of the parameter "a" in that case. Solution.  The differential of work calculated on exercise 6.2 is Here, d represents the dimension of the box. So The parameter a is the lenght, according to equation (67). Because we are working on  3 dimensions, a³=V . This might come from the definition of entropy*.      2. What do we get for DW for d=3 and n --> infinity? And how is this result related to the expected form DW = N k_B T dV/V?    Solution.  On the last expression we get DW for three dimensional case. Now, applying the limit on infinity, we expect that the differential of work would become on well potential one. So,   
Leer más

homework T06.3, a) and b)

Imagen
a) the code is: import numpy as np import matplotlib.pyplot as plt R=8.314 T=300 N=1 Va=1 Vb=2*Va g=5/3 Pa=N*R*T/Va Pb=Pa*(Va**g)/(Vb**g) l=np.arange(0,1,0.001) P1=l*Pb+(1-l)*Pa V1=l*Vb+(1-l)*Va V2=np.zeros(1000) P2=np.zeros(1000) for i in range (0,len(V2)):     V2[i]=Vb-i/1000     P2[i]=Pa*(Va**g)/(V2[i]**g)   c=P1[500]*(V1[500])**g V3=np.zeros(1000) P3=np.zeros(1000) for i in range (0,len(V2)):     V3[i]=Vb-i/1000     P3[i]=c/(V3[i]**g) plt.plot(V1,P1) plt.plot(V2,P2) plt.plot(V3,P3) plt.plot(V1[500],P1[500],"o") plt.show() and the plot is: pd: i'm sorry i don't know how to pass some latex to html so i put it like images
Leer más